3.260 \(\int \frac {(d+e x)^3}{b x+c x^2} \, dx\)

Optimal. Leaf size=64 \[ -\frac {(c d-b e)^3 \log (b+c x)}{b c^3}+\frac {e^2 x (3 c d-b e)}{c^2}+\frac {d^3 \log (x)}{b}+\frac {e^3 x^2}{2 c} \]

[Out]

e^2*(-b*e+3*c*d)*x/c^2+1/2*e^3*x^2/c+d^3*ln(x)/b-(-b*e+c*d)^3*ln(c*x+b)/b/c^3

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Rubi [A]  time = 0.06, antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {698} \[ \frac {e^2 x (3 c d-b e)}{c^2}-\frac {(c d-b e)^3 \log (b+c x)}{b c^3}+\frac {d^3 \log (x)}{b}+\frac {e^3 x^2}{2 c} \]

Antiderivative was successfully verified.

[In]

Int[(d + e*x)^3/(b*x + c*x^2),x]

[Out]

(e^2*(3*c*d - b*e)*x)/c^2 + (e^3*x^2)/(2*c) + (d^3*Log[x])/b - ((c*d - b*e)^3*Log[b + c*x])/(b*c^3)

Rule 698

Int[((d_.) + (e_.)*(x_))^(m_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d +
e*x)^m*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, m}, x] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*
e + a*e^2, 0] && NeQ[2*c*d - b*e, 0] && IntegerQ[p] && (GtQ[p, 0] || (EqQ[a, 0] && IntegerQ[m]))

Rubi steps

\begin {align*} \int \frac {(d+e x)^3}{b x+c x^2} \, dx &=\int \left (\frac {e^2 (3 c d-b e)}{c^2}+\frac {d^3}{b x}+\frac {e^3 x}{c}+\frac {(-c d+b e)^3}{b c^2 (b+c x)}\right ) \, dx\\ &=\frac {e^2 (3 c d-b e) x}{c^2}+\frac {e^3 x^2}{2 c}+\frac {d^3 \log (x)}{b}-\frac {(c d-b e)^3 \log (b+c x)}{b c^3}\\ \end {align*}

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Mathematica [A]  time = 0.03, size = 59, normalized size = 0.92 \[ \frac {b c e^2 x (-2 b e+6 c d+c e x)-2 (c d-b e)^3 \log (b+c x)+2 c^3 d^3 \log (x)}{2 b c^3} \]

Antiderivative was successfully verified.

[In]

Integrate[(d + e*x)^3/(b*x + c*x^2),x]

[Out]

(b*c*e^2*x*(6*c*d - 2*b*e + c*e*x) + 2*c^3*d^3*Log[x] - 2*(c*d - b*e)^3*Log[b + c*x])/(2*b*c^3)

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fricas [A]  time = 0.84, size = 97, normalized size = 1.52 \[ \frac {b c^{2} e^{3} x^{2} + 2 \, c^{3} d^{3} \log \relax (x) + 2 \, {\left (3 \, b c^{2} d e^{2} - b^{2} c e^{3}\right )} x - 2 \, {\left (c^{3} d^{3} - 3 \, b c^{2} d^{2} e + 3 \, b^{2} c d e^{2} - b^{3} e^{3}\right )} \log \left (c x + b\right )}{2 \, b c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3/(c*x^2+b*x),x, algorithm="fricas")

[Out]

1/2*(b*c^2*e^3*x^2 + 2*c^3*d^3*log(x) + 2*(3*b*c^2*d*e^2 - b^2*c*e^3)*x - 2*(c^3*d^3 - 3*b*c^2*d^2*e + 3*b^2*c
*d*e^2 - b^3*e^3)*log(c*x + b))/(b*c^3)

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giac [A]  time = 0.15, size = 87, normalized size = 1.36 \[ \frac {d^{3} \log \left ({\left | x \right |}\right )}{b} + \frac {c x^{2} e^{3} + 6 \, c d x e^{2} - 2 \, b x e^{3}}{2 \, c^{2}} - \frac {{\left (c^{3} d^{3} - 3 \, b c^{2} d^{2} e + 3 \, b^{2} c d e^{2} - b^{3} e^{3}\right )} \log \left ({\left | c x + b \right |}\right )}{b c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3/(c*x^2+b*x),x, algorithm="giac")

[Out]

d^3*log(abs(x))/b + 1/2*(c*x^2*e^3 + 6*c*d*x*e^2 - 2*b*x*e^3)/c^2 - (c^3*d^3 - 3*b*c^2*d^2*e + 3*b^2*c*d*e^2 -
b^3*e^3)*log(abs(c*x + b))/(b*c^3)

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maple [A]  time = 0.05, size = 103, normalized size = 1.61 \[ \frac {e^{3} x^{2}}{2 c}+\frac {b^{2} e^{3} \ln \left (c x +b \right )}{c^{3}}-\frac {3 b d \,e^{2} \ln \left (c x +b \right )}{c^{2}}-\frac {b \,e^{3} x}{c^{2}}+\frac {d^{3} \ln \relax (x )}{b}-\frac {d^{3} \ln \left (c x +b \right )}{b}+\frac {3 d^{2} e \ln \left (c x +b \right )}{c}+\frac {3 d \,e^{2} x}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^3/(c*x^2+b*x),x)

[Out]

1/2*e^3*x^2/c-e^3/c^2*x*b+3*d*e^2*x/c+1/c^3*b^2*ln(c*x+b)*e^3-3/c^2*b*ln(c*x+b)*d*e^2+3/c*ln(c*x+b)*d^2*e-1/b*
ln(c*x+b)*d^3+d^3*ln(x)/b

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maxima [A]  time = 1.35, size = 91, normalized size = 1.42 \[ \frac {d^{3} \log \relax (x)}{b} + \frac {c e^{3} x^{2} + 2 \, {\left (3 \, c d e^{2} - b e^{3}\right )} x}{2 \, c^{2}} - \frac {{\left (c^{3} d^{3} - 3 \, b c^{2} d^{2} e + 3 \, b^{2} c d e^{2} - b^{3} e^{3}\right )} \log \left (c x + b\right )}{b c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^3/(c*x^2+b*x),x, algorithm="maxima")

[Out]

d^3*log(x)/b + 1/2*(c*e^3*x^2 + 2*(3*c*d*e^2 - b*e^3)*x)/c^2 - (c^3*d^3 - 3*b*c^2*d^2*e + 3*b^2*c*d*e^2 - b^3*
e^3)*log(c*x + b)/(b*c^3)

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mupad [B]  time = 0.14, size = 65, normalized size = 1.02 \[ \frac {e^3\,x^2}{2\,c}-x\,\left (\frac {b\,e^3}{c^2}-\frac {3\,d\,e^2}{c}\right )+\frac {d^3\,\ln \relax (x)}{b}+\frac {\ln \left (b+c\,x\right )\,{\left (b\,e-c\,d\right )}^3}{b\,c^3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x)^3/(b*x + c*x^2),x)

[Out]

(e^3*x^2)/(2*c) - x*((b*e^3)/c^2 - (3*d*e^2)/c) + (d^3*log(x))/b + (log(b + c*x)*(b*e - c*d)^3)/(b*c^3)

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sympy [B]  time = 1.28, size = 112, normalized size = 1.75 \[ x \left (- \frac {b e^{3}}{c^{2}} + \frac {3 d e^{2}}{c}\right ) + \frac {e^{3} x^{2}}{2 c} + \frac {d^{3} \log {\relax (x )}}{b} + \frac {\left (b e - c d\right )^{3} \log {\left (x + \frac {- b c^{2} d^{3} + \frac {b \left (b e - c d\right )^{3}}{c}}{b^{3} e^{3} - 3 b^{2} c d e^{2} + 3 b c^{2} d^{2} e - 2 c^{3} d^{3}} \right )}}{b c^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**3/(c*x**2+b*x),x)

[Out]

x*(-b*e**3/c**2 + 3*d*e**2/c) + e**3*x**2/(2*c) + d**3*log(x)/b + (b*e - c*d)**3*log(x + (-b*c**2*d**3 + b*(b*
e - c*d)**3/c)/(b**3*e**3 - 3*b**2*c*d*e**2 + 3*b*c**2*d**2*e - 2*c**3*d**3))/(b*c**3)

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